# From what height did the lead ball fall without initial velocity if its temperature increased by 12

October 1, 2021 | education

| **From what height did the lead ball fall without initial velocity if its temperature increased by 12 ° C upon impact on the surface?**

Data: Δt (change in temperature of a given lead ball after impact) = 12 ºС; V0 (initial ball velocity) = 0 m / s.

Constants: Cc (specific heat capacity of lead) = 140 J / (kg * K); g (acceleration due to gravity) ≈ 10 m / s2.

To determine the initial height of a given lead ball, we apply the formula: Сс * m * Δt = m * g * h, whence h = Сс * Δt / g.

Calculation: h = 140 * 12/10 = 168 m.

Answer: The target ball was 168 m above the surface.

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